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6x^2=198
We move all terms to the left:
6x^2-(198)=0
a = 6; b = 0; c = -198;
Δ = b2-4ac
Δ = 02-4·6·(-198)
Δ = 4752
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{4752}=\sqrt{144*33}=\sqrt{144}*\sqrt{33}=12\sqrt{33}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-12\sqrt{33}}{2*6}=\frac{0-12\sqrt{33}}{12} =-\frac{12\sqrt{33}}{12} =-\sqrt{33} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+12\sqrt{33}}{2*6}=\frac{0+12\sqrt{33}}{12} =\frac{12\sqrt{33}}{12} =\sqrt{33} $
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